No, here when Thread-1 is in synchronized method1() it must be holding lock on object’s monitor and will release lock on object’s monitor only when it exits synchronized method1(). So, Thread-2 will have to wait for Thread-1 to release lock on object’s monitor so that it could enter synchronized method2().
Likewise, Thread-2 even cannot enter synchronized method1() which is being executed by Thread-1. Thread-2 will have to wait for Thread-1 to release lock on object’s monitor so that it could enter synchronized method1().
Program >
class MyRunnable1 implements Runnable{
@Override
public void run(){
if(Thread.currentThread().getName().equals("Thread-1"))
method1();
else
method2();
}
synchronized void method1(){
System.out.println(Thread.currentThread().getName()
+" in synchronized void method1() started");
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println(Thread.currentThread().getName()
+" in synchronized void method1() ended");
}
synchronized void method2(){
System.out.println(Thread.currentThread().getName()
+" in synchronized void method2() started");
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println(Thread.currentThread().getName()+
" in synchronized void method2() ended");
}
}
/** Copyright (c), AnkitMittal JavaMadeSoEasy.com */
public class MyClass {
public static void main(String args[]) throws InterruptedException{
MyRunnable1 myRunnable1=new MyRunnable1();
Thread thread1=new Thread(myRunnable1,"Thread-1");
Thread thread2=new Thread(myRunnable1,"Thread-2");
thread1.start();
Thread.sleep(10);//Just to ensure Thread-1 starts before Thread-2
thread2.start();
}
}
/*OUTPUT
Thread-1 in synchronized void method1() started
Thread-1 in synchronized void method1() ended
Thread-2 in synchronized void method2() started
Thread-2 in synchronized void method2() ended
*/
|
If you note output, when Thread-1 was is in synchronized method1() it was holding lock on object’s monitor. So, Thread-2 waited for Thread-1 to release lock on object’s monitor to enter synchronized method2().
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Situation based questions -
Suppose you have 2 threads (Thread-1 and Thread-2) on same object. Thread-1 is in synchronized method1(), can Thread-2 enter synchronized method2() at same time?
Suppose you have 2 threads (Thread-1 and Thread-2) on same object. Thread-1 is in static synchronized method1(), can Thread-2 enter static synchronized method2() at same time?
Suppose you have 2 threads (Thread-1 and Thread-2) on same object. Thread-1 is in synchronized method1(), can Thread-2 enter static synchronized method2() at same time?
Suppose you have thread and it is in synchronized method and now can thread enter other synchronized method from that method?
Suppose you have thread and it is in static synchronized method and now can thread enter other static synchronized method from that method?
Suppose you have thread and it is in static synchronized method and now can thread enter other non static synchronized method from that method?
Suppose you have thread and it is in synchronized method and now can thread enter other static synchronized method from that method?
Suppose you have 2 threads (Thread-1 on object1 and Thread-2 on object2). Thread-1 is in synchronized method1(), can Thread-2 enter synchronized method2() at same time?
Suppose you have 2 threads (Thread-1 on object1 and Thread-2 on object2). Thread-1 is in static synchronized method1(), can Thread-2 enter static synchronized method2() at same time?
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