Program to Sort Map by value in Ascending order by implementing Comparator interface and overriding its compare method

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.Set;

class SortByValue implements Comparator<Map.Entry<Integer, Integer>>{
   public int compare( Map.Entry<Integer,Integer> entry1, Map.Entry<Integer,Integer> entry2){
       return (entry1.getValue()).compareTo( entry2.getValue() );

* @author AnkitMittal
* Copyright (c), AnkitMittal
* Main class
public class SortMapByValueAscending {
   public static void main(String...a){
       Mapx<Integer, Integer> map = new HashMap<Integer, Integer>();
       map.put(1, 2);
       map.put(2, 1);
       map.put(3, 9);
       map.put(4, 8);
       Set<Entry<Integer, Integer>> entrySet = map.entrySet();
       List<Entry<Integer, Integer>> listOfentrySet = new ArrayList<Entry<Integer, Integer>>(entrySet);
       System.out.print("Before sorting by value: ");
       for(Map.Entry<Integer, Integer> entry:listOfentrySet){
        System.out.print(entry.getKey()+"="+entry.getValue()+"  ");
       Collections.sort(listOfentrySet, new SortByValue());
       System.out.print("\nAfter sorting by value(ascending): ");
       for(Map.Entry<Integer, Integer> entry:listOfentrySet)
        System.out.print(entry.getKey()+"="+entry.getValue()+"  ");
Before sorting by value: 1=2  2=1  3=9  4=8
After sorting by value(ascending): 2=1  1=2  4=8  3=9
Note : In the above program, only listOfentrySet obtained from map contain entry (key-value) pairs sorted on basis of values, map is not sorted on basis of values.

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